WebList list = [1, 2, 3, 4, 5, 6, 7]; int extraindex = -2; @override Widget build (BuildContext context) { return Scaffold ( body: Container ( child: ListView.builder ( itemCount: list.length % 2 == 0 ? list.length / 2 : … WebAug 18, 2024 · The only drawback is the added complexity to manage the filtered list : user can "delete" elements, add others etc... I thought of creating a parallel list of "index" containing the index of the elements that need to be displayed... but same thing, I believe it would create risks of problems linked to users acting on the list's content...
ListView In Flutter With Example Dynamic ListView
WebJul 12, 2024 · A VisibilityDetector widget wraps an existing Flutter widget and fires a callback when the widget's visibility changes. VisibilityDetector ( key: Key ('my-widget-key'), onVisibilityChanged: (visibilityInfo) { var visiblePercentage = visibilityInfo.visibleFraction * 100; debugPrint ( 'Widget $ {visibilityInfo.key} is $ {visiblePercentage ... Web2 days ago · I am using ListView horizontal and vertical scrolling and MouseRegion or Inkwell(onHover method) any other way working properly on Flutter web And Desktop devices properly but not mobile devices (IOS and Android). I am trying to make listView and GridView auto play when it focuses on the particular index for a few mill-second and the … dahlie rebeccas world
Stop Listview.builder in Flutter - Stack Overflow
WebAug 18, 2024 · 2. One way you can do this is something like this using ScrollController and NotificationListener. class MyWidget extends StatefulWidget { @override _MyWidgetState createState () => _MyWidgetState (); } class _MyWidgetState extends State { ScrollController sc = ScrollController (); int centerItemIndex; double screenHeight; … WebFeb 17, 2024 · Use isOdd or isEven to ignore some indexes. ListView.builder ( itemCount: myList.length itemBuilder: (_, index) { if (index.isEven) { return MyCustomTile ( first: myList [index] second: index + 1 == myList.length ? null : myList [index+1] ); } return Container (); } ) Attention to not get an index out of the bounds of your list Share WebJul 8, 2024 · ListView.builder ( itemCount: items.length, itemBuilder: (context, index) { return Visibility ( visible: index>5, child: ListTile ( title: Text ('$ {items [index]}'), ), ); }, ); Hope this helps! :D Share Improve this answer Follow answered Feb 12, 2024 at 13:17 Sleepingisimportant 916 4 7 Add a comment 0 dahlie ottos thrill